Find a point of the graph of the function v(x) = -3f(-x), given that (p,q) is a point on the graph y = f(x)
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Answer:
A
Step-by-step explanation:
Given
f(x) =
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
x + 3 = 0 → x = - 3 is the vertical asymptote