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zysi [14]
3 years ago
13

Write the prime factorization in expanded form for 36

Mathematics
1 answer:
asambeis [7]3 years ago
3 0
36 = 6\times 6 = 2\times 3\times 2\times 3=2^2\times 3^2
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Simplify -3+6i-(-5-3i)-8i​
borishaifa [10]

Answer:

2 +i

Step-by-step explanation:

-3+6i-(-5-3i)-8i​

Distribute the minus sign

-3 +6i +5 +3i -8i

Combine like terms

-3+5 +6i +3i -8i

2 +i

4 0
3 years ago
PLEASE HELP ME I NEED IT<br> X=<br> Y=
vampirchik [111]
X=33 and Y= 57



Step by step explanation if you see the right angle at 57 degrees it part of x so x plus 57 is 90 and 90 minus 57 is 33 so x is 33 and x and y also form a right angle so x plus y should equal 90 and 90 minus 33 is 7 so that’s Y
7 0
3 years ago
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−104=4x−4(2x+16)<br> I need a whole number i keep messing up
kotykmax [81]

Answer:

x=10

Step-by-step explanation:

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3 years ago
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What is the equation for the line of reflection that maps the trapezoid onto itself?
kvv77 [185]
The line that maps a figure onto itself is a line of symmetry of the figure.

From the given trapezoid, the line of symmetry of the trapezoid is x = -2.

Therefore, the <span>equation for the line of reflection that maps the trapezoid onto itself</span> is x = -2.
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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
3 years ago
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