Question

A straight wire 0.10 m long carrying a current of 2.0 A is at right angles to a magnetic field. The force on the wire is 0.04 N. What is the strength of the magnetic field?

Answer 1

Answer:

The strength of magnetic field is 0.2 Tesla.

Explanation:

Data from the question is

Length (L) of wire ; L=0.10 m

Current in wire ; I= 2.0 A

Force on wire ; F = 0.04 N

Angle = Right angle So, $\theta$$\thita = 90^{o}$

Now ,

We have to find the magnetic Field strength (B)

For this formula for Force on wire in magnetic field is

$F = I \times B \times L \times sin(\theta)$

Further modified as

$B = \frac{F}{I \times L \times sin(\theta)}$

Now insert values in the formula

$B = \frac{0.04N}{2.0A \times 0.10 m \times sin(90^{0})}$

$B = 0.2 T$

So, the strength of magnetic field is 0.2 Tesla.