Answer:

Explanation:
Consider the motion of the ball attached to string.
In triangle ABD

height gained by the ball is given as

= mass of the ball attached to string = 110 g
= speed of the ball attached to string just after collision
Using conservation of energy
Potential energy gained = Kinetic energy lost

Consider the collision between the two balls
= mass of the ball fired = 26 g
= initial velocity of ball fired before collision = ?
= final velocity of ball fired after collision = ?
using conservation of momentum

Using conservation of kinetic energy

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The sign associated with the average velocity of the object is negative.
<h3>
Average velocity of the object</h3>
The average velocity of the object is calculated as follows;
Average velocity = (v1 + v2)/2
v1 = -20/30 = -0.667 m/s
v2 = 20/50 = 0.4 m/s
Average velocity = (-0.667 + 0.4)/2
Average velocity = -0.134 m/s
Thus, the sign associated with the average velocity of the object is negative.
Learn more about average velocity here: brainly.com/question/6504879
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Answer:
Explanation:
Let's call the large box "1" and the smaller box "2". The equation for this works so that momentum is conserved, as the Law states.
That says that the momentum of the larger box plus the momentum of the smaller box before the collision has to equal the momentum of the combined masses since they stick together. Filling in:
[(4(12) + 2(0)] = [(4 + 2)v] and
48 + 0 = 6v so
v = 8 m/s to the right
Explanation:
Parameters
Number of oscillation = 40 oscillations
Time of oscillation = 128s
Formular
Period (T) = <u>No of oscillation</u>
Time taken
T = <u>128</u>
40
T=3.2s