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Roman55 [17]
3 years ago
13

Type the correct answer in each box.Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics
2 answers:
velikii [3]3 years ago
8 0

Answer:

y intercept is 1  1/3

equation is y = -1/6x + 4/3

x coordinate is -70  (-70,13)

Step-by-step explanation:

find M

m = 1 - (-1)/ 2 -1 4

m = -2/12 = -1/6

Find y intercept--Plug m and one point from above into y = mx + b

1 = - 1/6 (2) + b

1 = -2/6 + b

1  2/6 = b

1  1/3 = b

4/3 = b

To find the x coordinate if y is 13

13 = -1/6 x + 4/3

11 2/3 = -1/6 x

-70 = x

jeka943 years ago
7 0
<h2>Answer: </h2>

The y intercept of line AB = (0,\dfrac{4}{3})

The equation of line AB will be

y=\dfrac{-1}{6}x+\dfrac{4}{3}

The x-coordinate of C = 4

<h2>Step-by-step explanation:</h2>

The slope of line AB with coordinates of A and B are (14, -1) and (2, 1)

m_1=\dfrac{1-(-1)}{2-14}=\dfrac{2}{-12}=\dfrac{1}{-6}

The equation of line AB will be

(y-1)=\dfrac{1}{-6}(x-2)\\\\\Rightarrow y=\dfrac{1}{-6}(x-2)+1\\\\\Rightarrow\ y=\dfrac{-1}{6}x+\dfrac{1}{3}+1\\\\\Rightarrow y=\dfrac{-1}{6}x+\dfrac{4}{3}

Put x=0, we get the y=\dfrac{4}{3} i.e. (0,\dfrac{4}{3}) is the y intercept of line AB.

Since, Line AB and Line BC form a right angle at their point of intersection, B. The the product of their slope must be -1.

Therefore, the slope of BC =m_2=\dfrac{-1}{m_1}=6

Let x coordinate of C be a,then the coordinates of C = (a,13)

Now, slope of BC with points B(2,1) and C(a,13) will be

\dfrac{13-1}{a-2}=6\\\\\Rightarrow\ a-2=\dfrac{12}{6}\\\\\Rightarrow\ a-1=2\\\\\Rightarrow\ a=4

Hence, the x-coordinate of C = 4

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