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3 years ago

This is geometry plz

Mathematics

1 answer:

Sergio039 [100]3 years ago

7 0

Answer:

Step-by-step explanation:

a line parallel to the equation would have the same slope (7/8)

so what we know so far is

y = 7/8x + b

since it has to go through point C (-4, 8)

we’ll plug in those values for x and y (x = -4, y = 8)

8 = 7/8(-4) + b

8 = -28/8 + b

8 = -3.5 + b

b = 11.5

so the equation is

y = 7/8x + 11.5

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Answer:

b.15 inches

Step-by-step explanation:

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Professor Halen has 184 students in his college mathematics lecture class. The scores on the midterm exam are normally distribut

AURORKA [14]

Answer: 21

Step-by-step explanation:

Given : The scores on the midterm exam are normally distributed with

$\mu=72.3\\\\\sigma=8.9$

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For x=90

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$P(82$

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3 years ago

Find the equation of the line.

malfutka [58]

Answer:

y = 2/3x + 4

Step-by-step explanation:

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y = mx+ b

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2 years ago

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What is the exact perimeter of kite ? Show your work.

Afina-wow [57]

Answer:

The perimeter of the kite is 29 units.

Step-by-step explanation:

1. Let's use the Pythagorean Theorem to find the perimeter of the kite:

With the information given, we have four right triangles with a new point A, intersecting UW and VX. Those triangles are:

Δ UVA

Δ VWA

Δ UXA

Δ XWA

As we can see in the figure, length of UV and VW is the same and the length of UX and WX is also the same.

2. Let's find the value of UV and VW

UV is the hypotenuse of Δ UVA and it sides are 3 and 4 units length. So, we can calculate the length of UV this way:

Length of UV ² = UA ² + VA ²

Replacing with the real values:

Length of UV ² = 3 ² + 4 ²

Length of UV ² = 9 + 16

Length of UV ² = 25

√Length of UV ² = √25

Length of UV = 5 units ⇒ Length of VW = 5 units

3. Let's find the value of UX and WX

UX is the hypotenuse of Δ UXA and it sides are 3 and 9 units length. So, we can calculate the length of UX this way:

Length of UX ² = UA ² + XA ²

Replacing with the real values:

Length of UX ² = 3 ² + 9 ²

Length of UX ² = 9 + 81

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√Length of UV ² = √90

Length of UV = 9.5 units (rounding to the nearest tenth) ⇒ Length of WX= 9.5 units

4. Let's calculate the perimeter of the kite:

Perimeter of the kite = UV + VW + WX + UX

Perimeter of the kite = 5 + 5 + 9.5 + 9.5

Perimeter of the kite = 29 units

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