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timama [110]
3 years ago
13

What is the answer to the problem (74x-47y)-(68x+21y)

Mathematics
1 answer:
Andrews [41]3 years ago
6 0
(74x-47y)-(68x+21y)
Add like-terms.
74x - 68x = 6x
-47y-(21y) = -68y
Your final answer is 6x-68y.
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Drinking 8 fluid ounces of milk provides 270.0 milligrams of calcium. How many fluid ounces of milk provide 72.5 milligrams of c
Margarita [4]
Set up a proportion:

\frac{8}{270} = \frac{x}{72.5}

The numerator represents fluid ounces of milk, and the denominator represents milligrams of calcium.

Simplify the first fraction to make multiplication easier:

\frac{8}{270} \div  \frac{2}{2} =  \frac{4}{135}
\frac{4}{135} = \frac{x}{72.5}

Cross multiply the fractions:

72.5 * 4 = 290
135x = 290

Divide both sides by 135 to get x by itself:

290 \div 135 = 2.1
x = 2.1


2.1 fluid ounces of milk provide 72.5 milligrams of calcium.
3 0
3 years ago
Read 2 more answers
Hector collects golf balls at a driving range. each bucket holds 39 golf balls. if hector has 43 buckets to fill, estimate how m
Alborosie
There are 1677 golf balls to fill all the buckets. Hope it help!
4 0
3 years ago
Factorize : y^3 -2y^2 -29y -42
AVprozaik [17]

Answer: (y-7)(y+3)(y+2)

Step-by-step explanation:

y^{3} -2y^{2}-29y-42\\\\(y^{2}-4y-21)(y+2)\\\\(y-7)(y+3)(y+2)\\\\

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

- Cutiepatutie ☺❀❤

7 0
3 years ago
Pratap puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2 and one half hours. Find the rate pratap can
N76 [4]

Answer:

<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2.5 hours.

We know that, Speed = \frac{Distance}{Time}

So, the <u>speed of Pratap with the current</u> will be:  (\frac{10}{2})miles/hour = 5 miles/hour

and the <u>speed of Pratap against the current</u> will be:  (\frac{10}{2.5})miles/hour = 4 miles/hour.

Suppose, the rate of Pratap in still water is x and the rate of current is y.

So, the equations will be........

x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)

Adding equation (1) and (2) , we will get......

2x=9\\ \\ x=\frac{9}{2}= 4.5

Now, plugging this x=4.5 into equation (1), we will get.....

4.5+y=5\\ \\ y=5-4.5 =0.5

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

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3 years ago
You have to pick 5 members of the student council to go to meeting. If there are 10 members total, how many 5 member teams can y
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