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4 years ago

7

Determine the x and y intercept for 2x + 5y - 20 = 0

1 answer:

SOVA2 [1]4 years ago

5 0

X-intercept:(10,0)
Y-intercept:(0,4)

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What equation can be used to show that the slope of the line is the same between any two points?

Blizzard [7]

If you think about slopes it will always be rise over run! Think of rise as climbing a mountain and run as in walking on the mountain you just climbed. In order to find an equation of any problem, you first need to look at a graph for your first clue. See if the line goes straight through the corners of certain places on the graph. If so than you just count rise over run!
In conclusion my thesis or solution for your question would be C.

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3 years ago

Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5

kobusy [5.1K]

Answer:

max{x²-4x²+5} = 5 at x = 0

Step-by-step explanation:

1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.

$f'(x)=0$

We get:

$f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0$

So the critical number is x = 0.

2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:

$f'(x)$ is positive when the x < 0 (for example: -6*(-1)=+)

$f'(x)$ is negative when the x > 0 (for example: -6*(1)=-)

Therefore, you have a local maximum.

Now just get the Y value by plugging in the critical number in the original function. $f(0)=5$

local maximum is (0,5)

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2 years ago

Which angles are corresponding angles?

vodomira [7]

Answer:

b

Step-by-step explanation:

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3 years ago

{(−1, 5), (2, 8), (5, 3), (13, −4)} what are the range

makkiz [27]

$(x;\ y)\\\\(-1, \fbox5), (2, \fbox8), (5, \fbox3), (13, \fbox{-4})\\\\\boxed{The\ range:y\in\{-4;\ 3;\ 5;\ 8\}}$

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3 years ago

Look at the figure and answer

andreyandreev [35.5K]

Answer:

$\cos x=\dfrac{8}{f}$

Step-by-step explanation:

Given that,

$\tan x=\dfrac{e}{8}\\\\\sin x=\dfrac{e}{f}$

We need to find the value of cos x.

We know that,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

Using the above relation,

$\dfrac{e}{8}=\dfrac{\dfrac{e}{f}}{\cos x}\\\\\cos x=\dfrac{\dfrac{e}{f}}{\dfrac{e}{8}}\\\\=\dfrac{e}{f}\times \dfrac{8}{e}\\\\=\dfrac{8}{f}$

So, the value of cos x is equal to $\dfrac{8}{f}$ .

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3 years ago