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2 years ago

What is the median for the data set?

Mathematics

1 answer:

GarryVolchara [31]2 years ago

8 0

260.5 is the median for the data set hope this helps;)

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Decide whether each table could represent a proportional relationship. If the

Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = $\frac{w}{b}$

Number of buses (b) Number wheels (w) Wheels per bus $(\frac{w}{b})$

5 30 $\frac{30}{5}=6$

8 48 $\frac{48}{8}=6$

10 60 $\frac{60}{10}=6$

15 90 $\frac{90}{15}=6$

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = $\frac{w}{t}$

Number of train cars(t) Number of wheels(w) Wheels per train car ( $\frac{w}{t}$ )

20 184 $\frac{184}{20}=9.2$

30 264 $\frac{264}{30}=8.8$

40 344 $\frac{344}{40}=8.6$

50 424 $\frac{424}{50}=8.48$

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

5 0

2 years ago

Select the correct answer.

Tpy6a [65]

Answer:

your answer is D.

Step-by-step explanation:

Using sine will give you 3*square root of 3

3 0

3 years ago

Read 2 more answers

Help please? Will mark correct and first answer as brainliest!! : )

Gelneren [198K]

Answer:

It Is O. 8

Step-by-step explanation:

Because you are suppose to round the number to the one in front of the other number

3 0

3 years ago

Read 2 more answers

Answer these 2 questions please

Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

$\frac{7}{8}-\frac{1}{4}$

Now, to subtract these, we want to make it so the denominators are the same, or the numbers on the lower half are the same. (One way to explain why this is true is: $\frac{a}{b}-\frac{c}{b}=a\frac{1}{b}-c\frac{1}{b}=(a-c)\frac{1}{b}=\frac{a-c}{b}$ ). Now, to make it so the denominators are the same, we can multiply the second fraction, 1/4, by 2/2 as 2/2 is essentially 1, and multiplying by 1 will get the same result, just with a denominator switched in this case. Doing this, we get:

$\frac{7}{8}-\frac{1}{4}\cdot\frac{2}{2}$

$\frac{7}{8}-\frac{2}{8}$

Now, subtracting the numerators, we get:

$\frac{5}{8}$ yards of string will remain.

Question 2:

For this, we are combining these two thicknesses, and thus we add 1/4 to 7/12. This gives us the equation:

$\frac{1}{4}+\frac{7}{12}$

Now, we again want to make it so the denominators are the same. (Here's a similar proof but for addition this time: $\frac{a}{b}+\frac{c}{b}=a\frac{1}{b}+c\frac{1}{b}=(a+c)\frac{1}{b}=\frac{a+c}{b}$ ). Now, to make the denominators the same, we can multiply the first fraction, 1/4, by 3/3 (also equivalent to 1). Doing this, we get: