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julia-pushkina [17]
4 years ago
7

Calculate the average net charge on phenylalanine if it is in a solution that has a ph of 8.70.

Chemistry
1 answer:
Alex Ar [27]4 years ago
5 0
Phenylalanine has two known pKa charges: 1.83 and 9.13. To determine their individual ionic dissociation charges at pH 10, the equation to be used is

pH = pKa + log [α/(1-α)]

At pKa 1.83:
10 = 1.83 + log [α₁/(1-α₁)]
α₁ = 0.99999

At pKa 9.13:
10 = 9.13 + log [α₂/(1-α₂)]
α₂ = 0.88114

Average Net Charge =  0.99999 + 0.88114 = 1.88
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A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use thi
Ber [7]

Answer:

M = 0.138 M

Explanation:

Given data:

Mass of glucose = 12.55 g

Volume of solution = 500 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 12.55 g/ 180.156 g/mol

Number of moles = 0.069 mol

Volume in L:

500 mL × 1 L /1000 mL

0.5 L

Molarity:

M = 0.069 mol / 0.5 L

M = 0.138 M

8 0
3 years ago
A 996.9 g sample of ethanol undergoes a temperature change of -70.98 °C while releasing 62.9
Volgvan

Answer:

c=3.71\ J/g^{\circ} C

Explanation:

Given that,

Mass of sample, m = 996.9 g

The change in temperature of the sample, \Delta T=-70.98^{\circ}C

Heat produced, Q = 62.9  calories = 263173.6 J

The heat released by a sample due to change in temperature is given by :

Q=mc\Delta T

Where

c is the specific heat capacity

So,

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{263173.6}{996.9\times 70.98}\\\\c=3.71\ J/g^{\circ} C

So, the specific heat of ethanol is equal to 3.71\ J/g^{\circ} C.

3 0
4 years ago
using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0
3 years ago
How do I solve for V1 in this equation ​
arlik [135]

Answer:

<h2>V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}</h2>

Explanation:

\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

<u>First of all cross multiply</u>

That's

P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}

<u>Next divide both sides by </u>P_{1}T_{2}<u>  in order to isolate </u>V_{1}

We have

\frac{P_{1}V_{1}T_{2}}{P_{1}T_{2}} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

We have the final answer as

V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

Hope this helps you

3 0
4 years ago
Calcium is a metal.
kirza4 [7]

Answer:

22.22 g

Explanation:

The balanced reaction equation is;

Ca(s) + 2HCl(aq) → CaCl2(aq) + H2(g)

Number of moles of calcium reacted = 8.02g/40.1g/mol = 0.2 moles of Calcium

From the reaction equation;

1 mole of Ca yields 1 mole of CaCl2

Hence 0.2 moles of Ca also yields 0.2 moles of CaCl2

Mass of calcium chloride produced = number of moles * molar mass

Mass of calcium chloride = 0.2 moles of CaCl2 * 111.1g/mol = 22.22 g

3 0
3 years ago
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