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Anvisha [2.4K]
3 years ago
12

Calcium is a metal.

Chemistry
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

22.22 g

Explanation:

The balanced reaction equation is;

Ca(s) + 2HCl(aq) → CaCl2(aq) + H2(g)

Number of moles of calcium reacted = 8.02g/40.1g/mol = 0.2 moles of Calcium

From the reaction equation;

1 mole of Ca yields 1 mole of CaCl2

Hence 0.2 moles of Ca also yields 0.2 moles of CaCl2

Mass of calcium chloride produced = number of moles * molar mass

Mass of calcium chloride = 0.2 moles of CaCl2 * 111.1g/mol = 22.22 g

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Vinvika [58]

Answer:

GOOD MORNING DIDI be happy

8 0
3 years ago
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Many portable gas heaters and grills use propane, C3H8(g). Using enthalpies of formation, calculate the quantity of heat produce
Elodia [21]

Answer:  600 kJ

-

Explanation:

                        C₃H₈ (g)  + 5 O₂ (g) =============== 3 CO₂ (g)  +  4 H₂O (l)

Δ⁰Hf   kJ/mol       -104             0                                       -393.5         -285.8

Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104)  kJ/mol

Δ⁰Hcomb = 2219.70 kJ/mol

n= m /MW   MW c₃H₈ = 44.1 g/mol

n= 12 g/44.1 g/mol = 0.27 mol

then for 12 g the heat released will be

0.27 mol x 2219.70 kJ/mol =  600 KJ

4 0
3 years ago
Read 2 more answers
Given the equation I = Q/t, solve for t.
larisa86 [58]

Answer: t=\frac{Q}{I}

Explanation:

I=\frac{Q}{t}

Multiply by t on both sides.

t*I=\frac{Q}{t}*t

tI=Q

Now divide by I to isolate t.

\frac{tI}{I}=\frac{Q}{I}

t=\frac{Q}{I}

5 0
3 years ago
The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air
IceJOKER [234]

Answer:

1.75\cdot 10^{-4} M

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

S = k_H p^o

Where k_H is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

S_1 = 2.67\cdot 10^{-4} M

Also, at sea level, we have an atmospheric pressure of:

p = 1.00 atm

Given mole fraction:

\chi_{O_2} = 0.209

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

p^o = \chi_{O_2} p

Then the equation becomes:

S_1 = k_H \chi_{O_2} p

Solve for k_H:

k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

p = 0.657 atm

Apply Henry's law using the constant we found:

S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M

8 0
3 years ago
For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-
Bond [772]

Answer:

C_t=0.165M

Explanation:

From the question we are told that:

Slope K=0.056 M-1 s -1

initial Concentration C_1=2.2M

Time t=100

Generally the equation for Raw law is mathematically given by

\frac{1}{C}_t=kt+\frac{1}{C}_0

\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0

C_t=0.165M

4 0
3 years ago
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