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Nataly_w [17]
3 years ago
12

You are shown \angle MNO∠MNO below whose measure is 152^{\circ}.152 ∘ . Draw an angle bisector of \angle MNO∠MNO by clicking a d

ragging a ray out from the vertex at N.N.
Mathematics
1 answer:
Flauer [41]3 years ago
4 0
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Mr.Martin is giving a math test next period.The test,which is worth 100 points,has 29 problems. Each problem is worth either 5 p
blsea [12.9K]

Answer:

The second option

Step-by-step explanation:

x+y=29

5x+2y=100

then y=29–x

since 5x+2y=100

then 5x+2(29–x)=100

then 5x+58–2x=100

then 3x+58=100

then 3x=100–58

then 3x=42

then x=42/3

then x=14

then y=29–14=15

5 0
4 years ago
Read 2 more answers
Can the gcf of 16 and 42 be less than 16????<br><br> Please answer
zubka84 [21]
Yes.

Since 16 isn't a factor of 42, your GCF would be 2.

Hope that helps. -UF aka nadia
3 0
3 years ago
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Food pill: $9<br> Sales tax:6%<br> Tip:20%<br><br> Can you help me please
steposvetlana [31]

Answer: $11.45

Step-by-step explanation:

Food pill: $9

Tax: 6%

Tip: 20%

x=(9)+(9)(0.06)+[(9)+(9)(0.06)](0.20)\\x=11.45

3 0
4 years ago
Rectangle has diagonal of 28 and forms a60 degree angle with the bases what are the side lengths
Anna71 [15]
Sine (28) = opposite / hypotenuse =
0.46947 = opposite / 28
opposite = 0.46947 * 28
<span><span><span>opposite side = 13.14516 </span> </span> </span>

cosine (28) = adjacent / hypotenuse =
0.88295 = adjacent / 28
adjacent = 28 * .88295
<span><span><span>adjacent side = 24.7226 </span>

Double Check

</span> </span> <span>13.14516^2 + 24.7226^2 = 28^2
</span>
<span> <span> <span> 172.7952314256  </span> </span> </span> + <span> <span> <span> 611.20695076 </span> </span> </span> = 784

<span> <span> <span> 784.0021821856 </span> </span> </span> = 784

Correct to 5 significant figures


7 0
3 years ago
Safe wheelchair ramp specifications require about 4.75° maximum angle to be constructed with the ground. At a particular buildin
NeTakaya

Answer:

The ramp must cover a horizontal distance of approximately 19.081 feet.

Step-by-step explanation:

Given the vertical distance (y), measured in feet, and the angle of the wheelchair ramp (\theta), measured in sexagesimal degrees. The horizontal distance needed for the ramp (x), measured in feet, is estimated by the following trigonometrical expression:

x = \frac{y}{\tan \theta} (1)

If we know that y = 1\,ft and \theta = 3^{\circ}, then the horizontal distance covered by this ramp is:

x = \frac{1\,ft}{\tan 3^{\circ}}

x \approx 19.081\,ft

The ramp must cover a horizontal distance of approximately 19.081 feet.

4 0
3 years ago
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