Question

Find the coordinate of centerof the ellipsex2 + 36y2 + 12x = 0​

Answer 1

Answer:

(-6, 0).

Step-by-step explanation:

x^2 + 36y^2 + 12x = 0

Convert to standard form:

(x + 6)^2 - 36 +36y^2 = 0

(x + 6)^2 + 36y^2 = 36

Divide through by 36:

(x + 6)^2 / 36 + (y - 0)^2/ 36 = 1

Now compare this with the general form:

(x - h)^2/a^2 + (y - k)^2/ b^2  = 1

We see that the center (h, k) = (-6, 0).