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lord [1]
4 years ago
9

Ms. Turner drove 825 miles in March. She drove 3 times as many miles in March as she did in January. She drove 4 times as many m

iles in February as she did in January. What was the total number of miles Ms. Turner drove in February?
Mathematics
1 answer:
navik [9.2K]4 years ago
4 0
825/3 = 275 which is how many miles she drove in January.

275*4= 1100 which is how many miles she drove in February. 

Ms. Turner drove 1100 miles in February. 
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Answer:

The solution is x = 0.5

Step-by-step explanation:

We need to write everything as a power of 3.

We know that:

\sqrt{a} = a^{0.5}

So

\sqrt{3} = 3^{0.5}

And

9 = 3^{2}

This following property is also important:

\frac{a^{b}}{a^{c}} = a^{b-c}

To solve, the first step is putting everything with the variable x on one side and everything without the variable x on the other side

\sqrt{3}.3^{3x} = 9

3^{0.5}.3^{3x} = 3^{2}

3^{3x} = \frac{3^{2}}{3^{0.5}}

3^{3x} = 3^{2-0.5}

3^{3x} = 3^{1.5}

This means that:

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Answer:

The standard error of the sample mean is _17.677_ psi.

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of n = 8 specimens is collected.

Given sample size is n = 8

Given mean of the population 'μ' = 2500 psi

standard deviation 'σ' = 50 psi

Let x⁻ is the mean of the observed sample

Standard error of the sample mean = \frac{S.D}{\sqrt{n} }      ...(i)

Given Population of standard error (S.D) 'σ' = 50 psi

Now substitute all values in (i)

S.E = \frac{50}{\sqrt{8} } =17.677

<u>Conclusion</u>:-

The standard error of the sample mean is _17.677psi.

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