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mina [271]
2 years ago
14

Can someone please tutor me on Alger because that’s my most failing class and I often need help with simple problems every one c

an answer but me for example this “-2(n-9)+4” and if ur willing to tutor comment and I will contact u through email or just in some kinda way or on here please n ty...btw I am in 7th grade n I am 13
Mathematics
1 answer:
kotykmax [81]2 years ago
4 0

Enlist your parents help to find you a decent tutor, it is much better to meet face to face.

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Is​ f(x) continuous at x equals 4​? Why or why​ not? A. ​No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit
soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0
2 years ago
Clare has a recipe for yellow cake. She uses 913 cups of flour to make 4 cakes. Noah will follow the same recipe. He will make c
lidiya [134]

Answer:

f/c

Step-by-step explanation:

it is bcs 913/4 and the same concept is used

7 0
3 years ago
Rewrite the following expression using the distributive property: 12x + 20
Dmitry_Shevchenko [17]

Answer: 4(3x +5) or 2(6x +20)

Step-by-step explanation:

8 0
2 years ago
Are my answers correct
lyudmila [28]
Yes your answers look correct nice job
3 0
3 years ago
Read 2 more answers
Hepp I am being timeddd​
Lorico [155]
The answer is Megan



following me on ig for tutoring
7 0
3 years ago
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