All categories

3 years ago

What is the LCM of 7 and 13

Mathematics

1 answer:

lutik1710 [3]3 years ago

3 0

Answer:

91 .

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly. Glad I could help!!

You might be interested in

Solve the given equation<br> 16 - 5(3w - 4) = 8(-2w + 11)

KIM [24]

Answer:

16-15w+20=-16w+88

-15w+16w=88-16-20

w=52

5 0

3 years ago

Which of the data sets below has a mean of 32? Select all that apply.

Akimi4 [234]

Answer:

B is the correct answer

Step-by-step explanation: When you add 18+54+24=96 divide 96 by 3 and its 32!

5 0

2 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago

Solve for y2. d = y2- y1

kvasek [131]

D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.

D+y1=y2 that drops -y1 for the right side but the left remains.

And that's your answer.

8 0

3 years ago

In a fitness club, the ratio of male and female is 3:2. Base on their ability level, they are group into 3 different groups, A,B

ArbitrLikvidat [17]

Answer:35, 1

Step-by-step explanation:

8 0

3 years ago