The absolute value of 5
1 answer:
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For odd function f(-x)= -f(x)
1) f(-x)= sin(-x) = -sin(x)=-f(x) sin is odd function
2) f(-x) = sin(-2x) = -sin 2x=-f(x)
3) f(-x)= (-x)³+1 = -x³ +1 (not an odd function)
To be an odd function, it should be like this:
if a function is (x³+1), to be odd f(-x) should be -(x³+1)=-x³-1
4) f(x)= x/(x²+1)
f(-x) = (-x)/((-x)²+1)= -x/(x²+1)=-f(x)
So, f(-x) gives
,
that means that f(x)= x/(x²+1) is an odd function.
5)f(x) = ∛(2x)
f(-x) = ∛(2*(-x)=∛(2x*(-1)) = ∛(2x)*∛(-1)=- ∛(2x)= -f(x)
1) f(-x)= sin(-x) = -sin(x)=-f(x) sin is odd function
2) f(-x) = sin(-2x) = -sin 2x=-f(x)
3) f(-x)= (-x)³+1 = -x³ +1 (not an odd function)
To be an odd function, it should be like this:
if a function is (x³+1), to be odd f(-x) should be -(x³+1)=-x³-1
4) f(x)= x/(x²+1)
f(-x) = (-x)/((-x)²+1)= -x/(x²+1)=-f(x)
So, f(-x) gives
that means that f(x)= x/(x²+1) is an odd function.
5)f(x) = ∛(2x)
f(-x) = ∛(2*(-x)=∛(2x*(-1)) = ∛(2x)*∛(-1)=- ∛(2x)= -f(x)
Answer:
Step-by-step explanation:
The multiplicity of a root of a polynomial equation is the number of times it appears in the solution.
Multiplicity is important because it can tell us two things about the polynomial that we work on and how it is graphed. first: it tells us the number repeating factor a polynomial has to determine the number of the real (positive or negative) roots and complex roots of the polynomial.
About graph behaves at the roots : Behavior of a polynomial function near a multiple root
The root −4 is a 'simple' root (of multiplicity 1), and therefore the graph crosses the x-axis at this root. The root 1 is of even multiplicity and therefore the graph bounces off the x-axis at this root.
