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Rama09 [41]
3 years ago
15

How to solve 42=3(2-3h)

Mathematics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

h= -4.

Step-by-step explanation:

42= 6-9h

42-6=-9h

36=-9h

36/-9= -9h

-4=h

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3 years ago
Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to
julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

\frac{dCA}{dV} = \frac{-kCA}{V0}

The integral of the above equation is:

\int\limits {\frac{dCA}{dV} } = \int\limits{\frac{-kCA}{V0} }

Re-organizing the integrals:

\int\limits  {\frac{dCA}{CA} } = \int\limits {\frac{-kdV}{V0} }

Integrating:

ln(CA) - ln(CA0) = \frac{-kV}{V0}

Inputting the initial conditions of CA and the values of k and V0:

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-2.659 = -0.00286V

=> V = \frac{2.659}{0.00286}

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0
3 years ago
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It is given in the question that

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The answer to this question is:

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