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Rudik [331]
2 years ago
8

Please help do not answer if u don't know the answer

Mathematics
1 answer:
Kisachek [45]2 years ago
8 0

Answer:

C

Step-by-step explanation:

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Determine the verticle asymptote and horizontal asymptote of x^2-25/2x^+13x+15?
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satela [25.4K]

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\frac{1}{2}

Step-by-step explanation:

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2 years ago
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Which statement is true about the function f(x)=-√-x
Harrizon [31]

Answer: D.The domain and range of the function are the same.


Step-by-step explanation: Given function f(x)=-√-x.

The given function is a square root function and we have minus sign in front of x inside square root.

A square root always defined for positive values or 0.

In order to get a positive number or 0 inside square root, let us solve the inequality:

-x\geq 0

On dividing both sides by -1, the inequality sign would get flip and we get

<h3>Domain: x \leq 0.</h3>

We can see that we have a negative sign in front of square root. So, the value of f(x) would be always a negative number or 0.

<h3>Therefore, range would also be :x \leq 0..</h3><h3>Therefore, correct option is D option.</h3>
5 0
3 years ago
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
Marina86 [1]

Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

Since a is a multiple of 9, then a has the form a=9s for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form 12=c*b, for c an integer. Then b has the form b=\frac{12}{m}

Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
2 years ago
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