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steposvetlana [31]
3 years ago
9

It takes a runner 4 h, 3 min, 45 s to run a marathon. If the distance of a marathon is 42.2 km, what is the average speed of the

runner?
Physics
1 answer:
RideAnS [48]3 years ago
8 0
You need to convert the 4 hr 7 min 29 s all to the same unit to start off with, the best thing to do usually is to convert to the smallest unit so we convert to seconds:

29s = 29s, no need to change anything there

7min = 7 X 60s = 420s

4h = 4 X 60min = 240min, 240 X 60s = 14,400s

Now that we've converted all the time units to the same unit (seconds), we add them together:

29 + 420 + 14,400 = 14,849s

Generally when we talk about speed and are using seconds as our unit for time, we express speed in m/s (metres per second), so now we convert the kilometres to metres:

1 km = 1000 m, so 42.2 km = 42.2 X 1000 = 42,200m

Finally, we can use our formula:

42,200 / 14,849 = 2.841942218 m/s

(I kind of rushed the calculations a little bit so that figure may not be 100% accurate, but the method is definitely correct)

Hope this helped :)
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A 950-kg car strikes a huge spring at a speed of 22m/s (fig. 11-54), compressing the spring 5.0m. (a) what is the spring stiffne
alukav5142 [94]

(a) The spring stiffness constant of the spring is 18,392 N/m.

(b) The time the car was in contact with the spring before it bounces off in the opposite direction is 0.23 s.

<h3>Kinetic energy of the car</h3>

The kinetic energy of the car is calculated as follows;

K.E = ¹/₂mv²

K.E = ¹/₂ x 950 x 22²

K.E = 229,900 J

<h3>Stiffness constant of the spring</h3>

The stiffness constant of the spring is calculated as follows;

K.E =  U = ¹/₂kx²

k = 2U/x²

k = (2 x 229,900)/(5)²

k = 18,392 N/m

<h3>Force exerted on the spring</h3>

F = kx

F = 18,392 x 5

F = 91,960 N

<h3>Time of impact</h3>

F = mv/t

t = mv/F

t = (950 x 22)/(91960)

t = 0.23 s

Learn more about spring constant here: brainly.com/question/1968517

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Brandon has a Nissan GTR. He drives 198.5 miles in 2.3 hours. What is his average speed?
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Read 2 more answers
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