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IrinaK [193]
3 years ago
8

How can a organization encourage total person development among their employees.

Physics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

Paying for employees seminars and workshops related to their careers

Explanation:

To motivate personal development among employees, several things can be done. Among them, giving employees chance to present their own solutions to problems, exposing the employees to several global challenges and how to handle them, paying for employees seminars and workshops related to their own careers for professional development among other things.

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A 75kg man climbs the stairs to the fifth floor of a building. A total hieght of 16m. His potential energy has increased by
yKpoI14uk [10]

Answer:

11760 joules

Explanation:

Given

Mass (m) = 75kg

Height (h) = 16m

Required

Determine the increment in potential energy (PE)

This is calculated as thus:

PE = mgh

Where g = 9.8m/s²

Substitute values for m, g and h.

P.E = 75 * 9.8 * 16

P.E = 11760 joules

8 0
3 years ago
What is the most likely evidence of an energy transformation taking place when a skater glides over ice?
Triss [41]

Small tracks of water are left on the ice as kinetic energy is transformed into thermal energy

5 0
3 years ago
Read 2 more answers
Help please with question 2bii <br><br> The one that starts with calculate the average ....
Anna11 [10]

Answer:

add text fully or atleast add book name edition . solution is in picture.  chk pictures ignore b part

Explanation:

4 0
3 years ago
A cricket starts at the 5 meter mark on a ruler. It jumps to the 10 meter mark. Then, it jumps back to the 6 meter mark. Calcula
belka [17]

We have that the cricket’s displacement is  

D_t=9meters

From the Question we are told that

Start position  5 meter mark

It jumps to the 10 meter mark.

it jumps back to the 6 meter mark.

Generally the equation for cricket’s displacement. is mathematically given as

D_t=Initial +final(displacement)\\\\D_t=(10-5)+(10-6)

D_t=9meters

For more information on this visit

brainly.com/question/24273210?referrer=searchResults

4 0
2 years ago
A cement block accidentally falls from rest from the ledge of a 53.0-m-high building. When the block is 14.0 m above the ground,
katrin [286]

Answer:

0.405 seconds

Explanation:

Consider the amount of time it takes the block to fall from 53 m up to 14 m above the ground; then consider the amount of time it takes the block to fall from 53 m up to 2 m above  the ground.

First,     d = (1/2) gt^2    or     t=   ( 2 d / g)^1/2

= ( 2 × 39 / 9.8)^1/2 = 2.8212 seconds

Then, to fall from 53 down to 2 meters...

 d = (1/2) gt^2    or     t=   ( 2 d / g)^1/2

= ( 2 * 51/ 9.8 )^1/2 = 3.2262 seconds

So the amount of time it takes for the block to fall from 14 m upto 2 m above the ground

3.2262 - 2.8212 = 0.405 seconds      

this is how much time there is from when the man sees the block until it hits him. Not much time...

5 0
3 years ago
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