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solmaris [256]
3 years ago
7

How does sound travel through a medium?

Physics
2 answers:
tigry1 [53]3 years ago
8 0

Answer : Particles vibrate parallel to the direction the sound travels.

Explanation :

Sound is a longitudinal wave. The particles of medium moves in the direction of the propagation of the wave. The sound waves requires a medium to travel.

The longitudinal wave propagates in the form of compression and rarefaction. The distance between the compression and the rarefaction is called wavelength.

So, the correct option is (d) "  Particles vibrate parallel to the direction the sound travels".

Papessa [141]3 years ago
4 0
Particles vibrate parallel to the direction the sound travels. It's a longitudinal wave.
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The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.

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\alpha = \frac{\omega_{f}-\omega_{o}}{t} (1)

Where:

  • \omega_{o} - Initial angular speed, in revolutions per second.
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  • t - Time, in seconds.

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y t = 15\,s, then the angular acceleration of the disc is:

\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}

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The angular acceleration of the disc is \frac{1}{36} radians per square second.

ii) The number of rotations that the disk makes before it stops (\Delta \theta), in revolutions, is determined by the following formula:

\Delta \theta  = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha} (2)

If we know that \omega_{o} = \frac{5}{12}\,\frac{rev}{s}, \omega_{f} = 0\,\frac{rev}{s} y \alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}, then the number of rotations done by the disc is:

\Delta \theta = 3.125\,rev

The disc makes 3.125 revolutions before it stops.

We kindly invite to check this question on rotational motion: brainly.com/question/23933120

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