All categories

3 years ago

How does sound travel through a medium?

Physics

2 answers:

tigry1 [53]3 years ago

8 0

Answer : Particles vibrate parallel to the direction the sound travels.

Explanation :

Sound is a longitudinal wave. The particles of medium moves in the direction of the propagation of the wave. The sound waves requires a medium to travel.

The longitudinal wave propagates in the form of compression and rarefaction. The distance between the compression and the rarefaction is called wavelength.

So, the correct option is (d) " Particles vibrate parallel to the direction the sound travels".

Papessa [141]3 years ago

4 0

Particles vibrate parallel to the direction the sound travels. It's a longitudinal wave.

You might be interested in

At a speed of 0. 93 ccc, a spaceship travels to a star that is 8. 5 lyly distant. part a according to a scientist on earth, how

mart [117]

At a speed of 0. 93 ccc, a spaceship travels to a star that is 8. 5 ly distant part and according to a scientist on earth 2.3 years the trip takes.

Spacecraft

A spacecraft is a vehicle or machine designed to fly in outer space. A type of artificial satellite, spacecraft are used for a variety of purposes, including communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and transportation of humans and cargo.

Satellites, rovers, and space stations are collectively referred to as spacecraft. In science fiction, a big, manned spacecraft that is not a satellite is commonly referred to as a spaceship.

To learn more about the speed of a spaceship refer here:

brainly.com/question/10119971

#SPJ4

7 0

2 years ago

A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin

kap26 [50]

Answer:

a) $\omega \approx 219.911\,\frac{rad}{s}$ , b) $\alpha = 16.916\,\frac{rad}{s^{2}}$ , c) $a_{t} = 1.776\,\frac{m}{s^{2}}$ , d) $a_{n} = 5077.889\,\frac{m}{s^{2}}$ , e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) $v = 23.091\,\frac{m}{s}$ .

Explanation:

a) The maximum angular velocity of the fan is:

$\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$\omega \approx 219.911\,\frac{rad}{s}$

b) The angular acceleration of the fan is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}$

$\alpha = 16.916\,\frac{rad}{s^{2}}$

c) The magnitude of the tangential aceleration is:

$a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)$

$a_{t} = 1.776\,\frac{m}{s^{2}}$

d) The magnitude of the centripetal acceleration is:

$a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)$

$a_{n} = 5077.889\,\frac{m}{s^{2}}$

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

$v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)$

$v = 23.091\,\frac{m}{s}$

5 0

3 years ago

A charge of −20 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric

Alex73 [517]

Answer:

(a) $-6.76\times 10^{12}\ N/C$

(b) $-1.352\times 10^{13}\ N/C$

(c) $-7.2\times 10^{11}\ N/C$

Explanation:

(a)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 5 cm = 0.05 m

Coulomb's constant (k) = $9\times 10^{9}\ Nm^2/C^2$

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

$E=(\frac{kQ}{R^3})r$

Plug in the given values and solve for 'E'. This gives,

$E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.05\\\\E_{in}=-1.352\times 10^{14}\times 0.05\\\\E_{in}=-6.76\times 10^{12}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

(b)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 10 cm = 0.10 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

$E=(\frac{kQ}{R^3})r$

Plug in the given values and solve for 'E'. This gives,

$E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.10\\\\E_{in}=-1.352\times 10^{14}\times 0.10\\\\E_{in}=-1.352\times 10^{13}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

(c)

Given:

Charge on sphere (Q) = $-20\ \mu C=-20\times 10^{-6}\ C$

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 50 cm = 0.50 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r > R' from the center of sphere is given as:

$E=\dfrac{kQ}{r^2}$

Plug in the given values and solve for 'E'. This gives,

$E_{out}=(\frac{9\times 10^{9}\times -20}{(0.50)^2})\\\\E_{out}=-7.2\times 10^{11}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)$

8 0

4 years ago

What can be harmful depending on point of view

GenaCL600 [577]

This is what I think is harmful!

1.) Deadly gases (Example: Carbon Monoxide)

2.) Poison

3.) Snake bites

(There is to many to list :D)

Have a good Day/Night :D

3 0

4 years ago

If the temperature rises by 9. 9 degrees, what is the corresponding temperature increase in degrees celsius?

Yanka [14]

Main Answer:

Assume that the temperature rises by 9.9 F

Initial Temperatures will be C1, F1

Final temperatures will be C2, F1 + 9.9

The relation between celsius and fahrenheit temperature is as follows:

C = 5/9(F - 32)

Increase in temperature in celsius will be

C2 - C1 = F2 - F1

C2 - C1 = 5/9 ( F1 +9.9 -32) - 5/9 ( F1 -32)

C2 - C1 = 5/9 ( F1 +9.9 -32 - F1 +32)

C2 - C1 = 5/9 (9.9)

C2 - C1 = 5.5C

Explanation:

What is temperature?

Temperature is defined as the degree of coldness or hotness of an object or a substance. Generally, it is measured in various temperature scales. They are celsius, fahrenheit, kelvin.

To know more about temperature, please visit:

brainly.com/question/25677592

#SPJ4

7 0

2 years ago