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SCORPION-xisa [38]
3 years ago
10

If Jane has 3 3/4 dozen boxes of envelopes, and she ordered 11 1/2 dozen more, how many dozen boxes will she have in all?

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0

Answer:  The correct option is (C) 15\dfrac{1}{4}.

Step-by-step explanation:  Given that Jane has 3\dfrac{3}{4} dozen boxes of envelopes and she ordered 11\dfrac{1}{2} dozen more.

We are to find the total dozen of boxes that Jane will have.

The total dozen of boxes that Jane will have is equal to the sum of dozen of boxes she has now and the dozen of boxes she has ordered.

Therefore, the total dozen of boxes Jane will have is given y

3\dfrac{3}{4}+11\dfrac{1}{2}\\\\\\=\dfrac{15}{4}+\dfrac{23}{2}\\\\\\=\dfrac{15+46}{4}\\\\\\=\dfrac{61}{4}\\\\\\=15\dfrac{1}{4}.

Thus, the total dozen of boxes that Jane will have is 15\dfrac{1}{4}.

Option (C) is correct.

Debora [2.8K]3 years ago
3 0
Hi there:-)

She has=3+3/4=15/4
She ordered=11+1/2=23/2
Now how many she has in all
(15/4)+(23/2)=15 1/4 ...answer

15 1/4 means 15+1/4=15.25

Hope it helps
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A human has 1 head and 2 legs.
A horse has 1 head and 4 legs.

Let's make two equations from what we know.

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Let's call humans 'x' and horses 'y'

The total number of heads were 74.
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Our first equation is:
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Subtract the first equation from the second equation.

2x - 2x + 2y - 4y = 148 - 196
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That means that there were 24 horses.

We can plug back in y = 24 into our first equation to find out how many humans there were.

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More can be learned about the normal distribution at brainly.com/question/4079902

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