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rusak2 [61]
3 years ago
9

there are 266 students watching a play in the auditorium. there 10 rows with 20 students in each row and 5 rows with 8 students

in each row. how many students r sitting in each of the two remainingrows if each of those row has an equal number of students ?
Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0
Let x = number of students in each of the remaining rows

266 = (10 x 20) + (5 x 8) + 2x
266 - (10 x 20) - (5 x 8) = 2x
266 - 200 - 40 = 2x
26 = 2x
x = 26/2
x = 13
Zigmanuir [339]3 years ago
6 0
10 x 20 = 200
5 x 8 = 40 

266 - (200 + 40) = 26

26 ÷ 2 = 13students
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You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a
Karo-lina-s [1.5K]

Answer:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967      

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

\bar X=573 represent the sample mean

\mu population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=36-1=35

The Confidence level is 0.90 or 90%, the significance would be \alpha=0.1 and \alpha/2 =0.05, and the critical value for this case would be t_{\alpha/2}=1.690

And replacing we got:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967    

And the 90% confidence interval would be between [566.8033 and 579.1967]

6 0
3 years ago
Evaluate the following expression when b = -4 , -4.5b=
Elza [17]

Answer:

18

Step-by-step explanation:

The question is asking you to evaluate -4.5b, which is a simplified way of saying

-4.5 * b

Since we know that b = -4, we can insert that instead of b.

-4.5 * -4

The two negatives cancel each other out, so you're left with

4.5 * 4 = 18

6 0
3 years ago
Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with mea
Anika [276]

Answer:

About 3 years Speedy Jet printers be guaranteed.

Step-by-step explanation:

Given : Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with

mean \mu = 4 and standard deviation  \sigma = 0.78

If the company wishes to replace no more than 10% of the printers.

To find : How long should Speedy Jet printers be guaranteed ?

Solution :

Using Z- table,  

Z value corresponding to 10% or 0.10 = -1.28.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

The value of x is given by,

x=(z\times \sigma)+\mu

Substitute the values,

x=(-1.28\times 0.78)+4

x=-0.9984+4

x=3.0016

So, approx 3 years.

Therefore, About 3 years Speedy Jet printers be guaranteed.

8 0
3 years ago
The answer options are <br><br> 6.75<br> -1.5y<br> -3x<br><br> thank you :))
Sonja [21]

Answer:

-1.5y

Step-by-step explanation:

+y(–1.5) = -1.5y

This is how distribution works

8 0
3 years ago
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ivolga24 [154]

Answer:

true

Step-by-step explanation:

true

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3 years ago
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