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zloy xaker [14]
3 years ago
5

Can someone please explain how to solve this? And give me the answer?! THANK U !

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76

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<span>The complete question is shown in the attached image

<u><em>Answer:</em></u>
measure angle H = 42</span>°<span>

<u><em>Explanation:</em></u>
<u>There is a theorem that states that:</u>
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<u>In the given, we have:</u>
angle E is an exterior angle to triangle DFH
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<u>Based on the above rule:</u>
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<u>We are given that:</u>
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<u>Substitute with the givens in the above rule and solve for the measure of angle H as follows:</u>
angle E = angle D + angle H
87</span>°<span> = 45</span>°<span> + measure angle H
measure angle H = 87</span>°<span> - 45</span>°<span>
measure angle H = 42</span>°<span>

Hope this helps :)</span>

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