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padilas [110]
3 years ago
5

Which gas law (choices are Charles’ Law, Gay-Lussac’s Law, or Boyle’s Law) explains each scenario:

Chemistry
1 answer:
Paladinen [302]3 years ago
6 0

Air bags help lessen injuries in an automobile crash.  --> Boyle's law

A helium balloon decreases in size when you put it into a freezer.  --> Charle's law

A can of spray paint will explode if tossed into a fire --> Gay Lussac's Law

Explanation:

- Boyle's law states that for a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas (p) is inversely proportional to its volume (V):

p \propto V

- Charle's law states that for a fixed mass of an ideal gas kept at constant pressure, the volume of the gas (V) is proportional to its absolute temperature (T):

V\propto T

- Gay-Lussac's Law states that for a fixed mass of an ideal gas kept at constant volume, the pressure of the gas (p) is proportional to the absolute temperature (T):

p\propto T

We can now use these three laws to explain the mentioned phenomena:

Air bags help lessen injuries in an automobile crash.  --> Boyle's law. In fact, as the volume of the gas inside the air bag increases, the pressure exerted by the gas inside decreases, and since the temperature is constant, the pressure exerted by the airbag on the passenger will be lower.

A helium balloon decreases in size when you put it into a freezer.  --> Charle's law. When the balloon is put into the freezer, its temperature decreases, and since the pressure inside the freezer is approx. constant, the volume of the balloon decreases as well.

A can of spray paint will explode if tossed into a fire --> Gay Lussac Law. Due to the fire, the temperature of the gas inside the can increases; since the volume is constant, the pressure will increase, and at some point it will be large enouth to cause the can to explode.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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<h3>Answer:</h3>

28.96 kJ/°C

<h3>Explanation:</h3>

We are given;

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We are required to find the heat capacity of benzoic acid;

<h3>Step 1: Moles of benzoic acid </h3>

Moles = Mass ÷ molar mass

Molar mass of benzoic = 122.12 g/mol

Therefore;

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<h3>Step 2: Determine the specific heat capacity </h3>

Heat change for 1 mole = 3226.7 kJ

Moles of Benzoic acid = 0.0254 moles

But;

Specific heat capacity × ΔT = Moles × Heat change

  cΔT = nΔH

Therefore;

Specific heat capacity,c = nΔH ÷ ΔT

                                     = (3226.7 kJ × 0.0254 moles) ÷ 2.83°C

                                    = 28.96 kJ/°C

Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C

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anyanavicka [17]
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Answer:

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