What is the air speed of a unladen swallow?

What type of intermolecular forces are expected between 4-methylcyclohexanone molecules?

Keith_Richards [23]

The answer is dipole-dipole and dipole-induced dipole forces.

The dipole-induced dipole is a kind of interaction induced by a polar molecule by disturbing the arrangement of electrons.

In methyl cyclohexanone molecules, there is a permanent dipole moment due to dipole moment vectors not canceling.
There is induction of dipole by disturbing the electronic arrangement.
A permanent dipole moment is created in this interaction.
Dipole-dipole interactions are defined as the forces that is formed from the close linkage of permanent or induced dipoles.
These forces are called Van der Waal forces.
Proteins contain a large number of these interactions, which vary considerably in strength.

To learn more about dipole-dipole interactions visit:

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7 0

2 years ago

What is the best way to measure the age of the Earth and why? Explain how scientists do this.

UkoKoshka [18]

Explanation:

the best way to understand the age of the earth is to estimate the age of matirials in it

3 0

3 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.