Question

The value for ψ in root tissue was found to be -1.6 bars. If you place the root tissue in a 0.1 m solution of sucrose at 20°c in an open beaker, what is the ψ of the solution, and in which direction would the net flow of water be? (hint: remember your formula: ψs = -icrt & your pressure constant, r = 0.0831 liters bars/ m k)

Answer 1

Answer:

$\Psi=\Psi_s+\Psi_p$

$I=1;C=0.1;R=0.0831$

$T=20+273=293~C$

as beaker is open so

$\Psi_p=0$

$\Psi=\Psi_s\\\Psi=-2.43483$

As ψof solution is lower than the root tissue so water will move out of the root to the solution

Explanation: