All categories

3 years ago

The function can be used to find the volume of air inside a basketball given its radius. What does V(r) represent?

Mathematics

2 answers:

MaRussiya [10]3 years ago

8 0

Correct answer: "the volume of the basketball when the radius is r"

The V(r) is a function: you give it the value of radius r, and it returns the volume V.

emmainna [20.7K]3 years ago

6 0

<u>Answer:</u>

The correct answer option is: the volume of the basketball when the radius is r.

<u>Step-by-step explanation:</u>

V(r) represents the volume of the basketball when its radius is r. So for any value for the radius of the basketball, its volume is going to vary accordingly.

Hence, we can say that the function V(r) is dependent on the variable r which is the radius of the basketball. Therefore, by putting in different values of r, we can find the corresponding value of the volume of the basketball.

You might be interested in

A scientist measures a substance to be 0.6 grams. Calculate the percent of error in the measurement.

SIZIF [17.4K]

How knows this answer

3 0

2 years ago

What is 2+(9-5)x7-3/4

Cloud [144]

I got 9.75 hope it's right

5 0

2 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0

3 years ago

this past Sunday, the giants scored 9 less than twice the cowboys. the packers scored 14 points more than the giants. if the tea

Grace [21]

Let the score of cowboys is x
and giants make score 9 which is twice less than the cowboys score so
giants score will be = 2x -9
and packers scored 14 more than giants that is (2x - 9) + 14
now sum of their scores is equal to 81 it means:
x + (2x - 9) + (2x -9) + 14 = 81
x + 2x - 9 + 2x - 9 + 14 = 81
5x = 81 + 4
5x = 85
x = 17
packers scored = (2x - 9) + 14
= 2 (17) -9 + 14
=38 + 5 = 43 points

5 0

3 years ago

Suppose the interval [negative 3−3,negative 1−1] is partitioned into nequals=44 subintervals. What is the subinterval length

Kobotan [32]

Answer: Δx = 0.5

Step-by-step explanation:

We have the interval:

[−3, −1]

and we partition it into 4 equal intervals.

first, the range of our interval is equal to the difference between the extremes, this is:

-1 - (-3) = -1 + 3 = 2

Then, if we divide it into 4, we have 4 segments with a range of:

2/4 = 0.5

Then the subinterval delta is 0.5, and the 4 intervals are:

[−3, -2.5], [−2.5, −2], [−2, −1.5], [−1.5, −1]

6 0

3 years ago