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tiny-mole [99]
3 years ago
8

Convert each fraction to a decimal.. 2/5

Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

.4

Step-by-step explanation:

2/5 is the same as 4/10

0.4

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What number would you add to the equation below to complete the square?
Debora [2.8K]

Answer:

A. 25/4

Step-by-step explanation:

(5/2)^{2} = 25/4

3 0
3 years ago
Rewrite the given parametric equations in Cartesian from x(t) = 2t– 1 y(t) = 5t
docker41 [41]

Hi there!

\large\boxed{(-\frac{5}{3},-\frac{5}{3})}

We can begin by setting the two expressions equal to solve for t:

2t - 1 = 5t

Subtract 2t from both sides:

-1 = 3t

Divide both sides by 3:

t = -1/3

Plug in this value of t into x(t) and y(t):

x(-1/3) = 2(-1/3) - 1 = -2/3 - 1 = -5/3

y(-1/3) = 5(-1/3) = -5/3

Thus:

(-5/3, -5/3) are the corresponding coordinates.

7 0
3 years ago
SOMONE HELP ME I HAVE <br> TO DO THIS AFTER SCHOOL PLS ASAP!!!
Scrat [10]

Answer:

1 no

2 I don't know

3 no

4 yes

5 2.5 is the slope

6 -0.5

7 no slope

Step-by-step explanation:

1 no because the y overlaps

2 not sure

3 it over laps

4 it never overlaps

5 y=2.5x-3

6 y=-0.5x+1

7 no slope it's just x=-2

for the 5-7 you can type that into demos and get more info

y=mx+b

m is the slope and b is y intercept

3 0
3 years ago
Simplify x/12x+x^2 <br> Find the excluded values step by step
Leona [35]

Answer:

13/12 x²

Step-by-step explanation:

x / 12 x + x²

Rewrite

x / 12 x + x + x²

Write the division as fraction

1/12 x + x + x²

Calculate the product

1/12 x² + x²

calculate the sum

13/12 x²

8 0
3 years ago
Given that log_{a}(3) = 0.477 and
kipiarov [429]

Given:

\log_{a}(3) = 0.477,\log_{a}(5) = 0.699

To find:

The value of \log_{a}(0.6).

Solution:

We need to find the value of:

\log_{a}(0.6)

It can be written as

\log_{a}(0.6)=\log_a\left(\dfrac{6}{10}\right)

\log_{a}(0.6)=\log_a\left(\dfrac{3}{5}\right)

By using the property of logarithm, we get

\log_{a}(0.6)=\log_a(3)-\log_a(5)        [\because \log \dfrac{a}{b}=\log a-\log b]

\log_{a}(0.6)=\log_a(3)-\log_a(5)

On substituting the given values, we get

\log_{a}(0.6)=0.477-0.699

\log_{a}(0.6)=-0.222

Therefore, the values of \log_a(0.6) is -0.222.

6 0
3 years ago
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