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Troyanec [42]
3 years ago
15

Which is the most specific name for a quadrilateral with four congruent sides?

Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer: A rhombus.

Step-by-step explanation: A square can be defined as a rhombus which is also a rectangle – in other words, a parallelogram with four congruent sides and four right angles. A trapezoid is a quadrilateral with exactly one pair of parallel sides.

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Ralph has a balance of $1350 on his credit card, which he plans to pay off by making a payment of the same amount each month. Wh
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Answer:

The answer is 40$ because 40$ makes the most sense in this particular equation

Step-by-step explanation:

7 0
3 years ago
Which expression is equal to sec x° multiplied by cot x°?
Over [174]
Sec x is equal to 1/cosx, cot x is equal to cosx/sinx. cos x cancels, and you are left with 1/sinx. this is equal to cscx. Cosecant is : hypotenuse / opposite, so the answer is **D**
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Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

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6 0
3 years ago
7x^2 - 16x - 15<br>please help find the factored form​
myrzilka [38]

Step-by-step explanation:

7x^×2-16x-15

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8 0
3 years ago
I would like help ASAP please
erica [24]

Answer:

The measure of angle T is 135 degrees.

Step-by-step explanation:

Let's just say the measure of angles T and S are variables t and s.

So the equation would be...

t + s = 180

Since they are supplementary angles, they add up to 180.

Also, we know that t is 3 times s.

t = 3s

Now we can solve this system of equations.

Substitute 3s into t of the first equation.

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s = 45

Then, since we know that the measure of angle t is 3 times the measure of angle s, we can just multiply 45 by 3 and find the measure of angle t.

45 * 3 = 135

t = 135

So the measure of angle t is 135.

*<em>Just copied from my previous answer, don't know why you needed it again but here you go.</em>

7 0
3 years ago
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