Answer:
Check the explanation
Step-by-step explanation:
Let
and
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume
having with mean
and
having mean 
Also we have given the variance is constant
A)
We can test hypothesis as

For this problem
Test statistic is

Where

We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
We will take the common terms in the expressions-
Here in the expression, 3y is a common term.
So,


So, the answer is
Answer:
2.16
Step-by-step explanation:
The question is on mean absolute deviation
The general formula ,
Mean deviation = sum║x-μ║/N where x is the each individual value, μ is the mean and N is number of values
<u>Team 1</u>
Finding the mean ;

Points Absolute Deviation from mean
51 2
47 2
35 14
48 1
64 15
<u>Sum </u> 34
Absolute mean deviation = 34/5= 6.8
<u>Team 2</u>
Finding the mean

Points Absolute deviation from the mean
27 15.8
55 12.2
53 10.2
38 4.8
41 1.8
<u>Sum 44.8 </u>
Absolute deviation from the mean = 44.8/5 =8.96
Solution
Difference in mean absolute deviation of the two teams = 8.96-6.8 = 2.16
27.5 / 3.5 = 7.86; The average yearly snowfall was 7.86 inches.