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frez [133]
3 years ago
6

If you invest 300 dollars in an account at 7.5 percent interest per year simple interest how much will you bave in the account a

t the beggining of the 11th year
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
8 0

keeping in mind that the interest is accumulated as time passes by, so "at the beginning of the 11th year", we're in the 11th year, just beginning, however, only 10 years have passed by, so after 10 years then.


\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$300\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years\dotfill &10 \end{cases} \\\\\\ A=300[1+(0.075)(10)]\implies A=300(1.75)\implies A=525

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3 years ago
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4 0
3 years ago
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The function f(x)=Acosh(Cx)+Bsinh(Cx). I need help determining the value of constant C>0 when the second derivative f''(x)=25
Rus_ich [418]

Answer:

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Step-by-step explanation:

First, you need to remember that:

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6 0
2 years ago
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faltersainse [42]

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7 0
2 years ago
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katen-ka-za [31]
X/4 + 12 = 5
to isolate the variable the first step is to subtract 12 from both sides
x/4 + 12 - 12 = 5 - 12
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next, to get rid of the division by 4, multiply both sides by 4
(x/4)*4 = -7*4
x = -28
7 0
2 years ago
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