Here is how we get the answer....
First, replace f(x) with y . ...
Replace every x with a y and replace every y with an x .
Solve the equation from Step 2 for y . ...
Replace y with f−1(x) f − 1 ( x ) . ...
Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
If we firstly consider only the terms in x.
subtract 2x from both sides of the equation
⇒5+2x
−2x=2x−2x
+6
Observe that the x terms are eliminated and we are left with
5+0=0+6 that is 5=6 which is invalid
There is no solution to this equation.
Answer:
6x-11y=-13
Step-by-step explanation:
(x1,y1)=(3/2,2) and (x2,y2)=(-4,-1)
y-y1= y2-y1/x2-x1 (x-x1)
y-2=-3/-11/2(x-3/2)
=6/11(x-3/2)
11(y-2)=6x-9
11y-22=6x-9
6x-11y=9-22
6x-11y=-13
Answer:
Step-by-step explanation:
To write the quadratic in standard form, begin by writing it in vertex form
Where (h,k) is the vertex of the parabola.
Here the vertex is (-3,-2). Substitute and write:
To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.
The vertex form of the equation is 
.
To write in standard form, convert vertex form through the distributive property.
