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Sergeeva-Olga [200]
3 years ago
12

Which is true about the solution to the system of inequalities shown? y > 3x + 1 y 3x + 1 are solutions. Only values that sat

isfy y 3x + 1 or y < 3x – 3 are solutions. There are no solutions.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

The correct option is;

There are no solutions

Step-by-step explanation:

From the graph of the inequality, with the y-intercept = 1 and slope = 3 for the blue shaded inequality

The equation is y > 3x + 1

While that of the other red shaded inequality, the slope is 3 and the y-intercept = -3

The equation is y < 3x - 3

Given that the two inequalities are parallel line that their domains do not overlap, we have that there are no solutions as the y-coordinate values of  y > 3x + 1 are always larger for a given x-coordinate value than the y-coordinate value of y < 3x - 3.

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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
  • x_2=1,\ x_3=9;
  • x_2=2,\ x_3=8;
  • x_2=3,\ x_3=7;
  • x_2=4,\ x_3=6;
  • x_2=5,\ x_3=5;
  • x_2=6,\ x_3=4;
  • x_2=7,\ x_3=3;
  • x_2=8,\ x_3=2;
  • x_2=9,\ x_3=1;
  • x_2=10,\ x_3=0.

In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
  • x_2=1,\ x_3=8;
  • x_2=2,\ x_3=7;
  • x_2=3,\ x_3=6;
  • x_2=4,\ x_3=5;
  • x_2=5,\ x_3=4;
  • x_2=6,\ x_3=3;
  • x_2=7,\ x_3=2;
  • x_2=8,\ x_3=1;
  • x_2=9,\ x_3=0.

In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
  • for x_1=4 - 7 solutions;
  • for x_1=5 - 6 solutions;
  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
  • for x_1=9 - 2 solutions;
  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0
3 years ago
Read 2 more answers
(a) Find the common difference of an A.P. whose first term is 5 and the number of terms is 30 and sum 1455.
Alexxandr [17]
Sum = n/2[2a + (n - 1)d] where a = first term, n = number of terms and d = common difference

(a) 30/2(2 x 5 + (30 - 1) x d) = 1455
10 + 29d = 1455 / 15
29d = 97 - 10
d = 87 / 29 = 3

(b) 7/2(2 x 9 + (7 - 1)d) = 0
18 + 6d = 0
6d = -18
d = -3
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3 years ago
1. i’ll give you brainliest if u get this right
Allisa [31]

Answer:

Step-by-step explanation:

34 and m=7

6 0
2 years ago
How much is 0.97 to 0.465?
RoseWind [281]
It is a decrease by .505
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6. What does |-9| equal?
hichkok12 [17]

The absolute value makes it 9

7 0
3 years ago
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