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Sergeeva-Olga [200]
3 years ago
12

Which is true about the solution to the system of inequalities shown? y > 3x + 1 y 3x + 1 are solutions. Only values that sat

isfy y 3x + 1 or y < 3x – 3 are solutions. There are no solutions.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

The correct option is;

There are no solutions

Step-by-step explanation:

From the graph of the inequality, with the y-intercept = 1 and slope = 3 for the blue shaded inequality

The equation is y > 3x + 1

While that of the other red shaded inequality, the slope is 3 and the y-intercept = -3

The equation is y < 3x - 3

Given that the two inequalities are parallel line that their domains do not overlap, we have that there are no solutions as the y-coordinate values of  y > 3x + 1 are always larger for a given x-coordinate value than the y-coordinate value of y < 3x - 3.

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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the value of this expression when c = -4 and d = 10 ? \frac{1}{4} (c³ + d²)

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\frac{1}{4} (c³ + d²) where c = -4 and d = 10

<h3>To Find:-</h3>

The value of the expression \frac{1}{4} (c³ + d²)

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\frac{1}{4} (c³ + d²) [Given expression]

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