Question

A piece of aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. What is its density of the aluminum rounded to the nearest hundredth? Only enter numerical values, which can include a decimal point.

Answer 1

Answer:

6.87 g/mL

Step-by-step explanation:

The density of an object can be found by dividing the mass by the volume.

$density=\frac{mass}{volume}\\\\ d=\frac{m}{ v}$

We know that the aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. Therefore, the mass is 87.3 g and the volume is 12.7 mL.

$m= 87.3 g\\\\v=12.7 mL$

Substitute the values into the formula.

$d= \frac{87.3 g}{12.7 mL}$

Divide 87.3 g by 12.7 mL

$d=6.87401575 g/mL$

Round to the nearest hundredth. The 4 in the thousandth place tells us to leave the 7 in the hundredth place.

$d= 6.87 g/mL$

The density of the aluminum is about 6.87 grams per milliliter.