Sure I will give two examples
Application of tangents
1. If we are traveling in a car around a corner and we drive over something slippery on the round ( like water , ice or oil ) , our car starts to skid
It continue in a direction tangent to the curve
Application of tangents
2. Have you ever sat on a merry- go around
If yes , then you would understand
From your experience when I tell you that the force your experience is towards the centre of merry- go around but your velocity ( the tendency of motion) is in the way toward which your body pointing
Another way saying the same thing would be to let you know that your velocity at any point is tangent while force .
At any point is normal to the circle along which you are moving
Can you draw connection between both the ways of saying the same thing?
Have this two example help you
Good luck :D
Answer:
The value of t is 1.75 years.
Step-by-step explanation:
Given that simple interest formula is I = (P×R×T)/100. So you have to substitute the following values into the formula :
![i = \frac{prt}{100}](https://tex.z-dn.net/?f=i%20%3D%20%20%5Cfrac%7Bprt%7D%7B100%7D%20)
![let \: i = 350,p = 2400,r = \frac{25}{3}](https://tex.z-dn.net/?f=let%20%5C%3A%20i%20%3D%20350%2Cp%20%3D%202400%2Cr%20%3D%20%20%5Cfrac%7B25%7D%7B3%7D%20)
![350 = \frac{2400 \times \frac{25}{3} \times t }{100}](https://tex.z-dn.net/?f=350%20%3D%20%20%5Cfrac%7B2400%20%5Ctimes%20%20%5Cfrac%7B25%7D%7B3%7D%20%5Ctimes%20t%20%7D%7B100%7D%20)
![350 = \frac{20000t}{100}](https://tex.z-dn.net/?f=350%20%3D%20%20%5Cfrac%7B20000t%7D%7B100%7D%20)
![350 \times 100 = 20000t](https://tex.z-dn.net/?f=350%20%5Ctimes%20100%20%3D%2020000t)
![20000t = 35000](https://tex.z-dn.net/?f=20000t%20%3D%2035000)
![t = 35000 \div 20000](https://tex.z-dn.net/?f=t%20%3D%2035000%20%5Cdiv%2020000)
![t = 35 \div 20](https://tex.z-dn.net/?f=t%20%3D%2035%20%5Cdiv%2020)
![t = 1.75 \: years](https://tex.z-dn.net/?f=t%20%3D%201.75%20%5C%3A%20years)
Answer:
9, 40 and 41
Step-by-step explanation:
All right triangle have lengths that follow the Pythagorean Theorem (a²+b² = c²). Right triangles have one angle equal to 90°. The two shorter sides form the right angle and the side opposite the right angle is called the hypotenuse.
Using the lengths given, we can use guess and check to see what sum of two sides squared would equal a third side, or just plug them into the equation: a²+b² = c² and see what lengths fit this equation.
I recommend starting with squares you are familiar with:
9² + 40²= 81 + 1600 = 1681
Now, take the √1681 to find the length of 'c', or the hypotenuse:
√1681 = 41
Since these three lengths fit the Pythagorean Theoreom, the would form a right triangle.
Is the base (leght width) plus the areas of each of the four triangular faces
Reflected over the x-axis:
![A'(2,-5),B'(-3,-5),C'(3,3)](https://tex.z-dn.net/?f=A%27%282%2C-5%29%2CB%27%28-3%2C-5%29%2CC%27%283%2C3%29)
<span>. Hence, the original triangle is described by A'B'C'.</span>