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Lyrx [107]
2 years ago
8

In the previous lesson, you created SMART goals for yourself to extend from the start of the semester to the end of the semester

. This lesson introduced you to the various resources that are part of the course. How can these resources help you reach your goals?
Go back to your SMART goal chart from the previous lesson and alter one of the goals so that it incorporates the use of at least one resource.
Mathematics
2 answers:
Aleks [24]2 years ago
8 0

Answer:

Improve your growth attitude, be more proactive, learn to understand yourself, be persistent despite hurdles, learn to accept your limits, learn how to make successful decisions, practice thankfulness, and stay open-minded to new opportunities are some of the ways that SMART goals can assist you.

Step-by-step explanation:

I've done this before :)

MA_775_DIABLO [31]2 years ago
6 0
=+ hfjjcmfjcnfjcnhcncncmk smajeijsm 34
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Please help me i don’t understand this question at all.
Maru [420]

9514 1404 393

Answer:

  D.

Step-by-step explanation:

The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)

When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.

The only reasonable choice is D.

__

Your calculator can check this for you.

  √12/(√3 +3) ≈ 3.4641/(1.7321 +3)

  = 3.4641/4.7321 ≈ 0.7321 = -1 +√3

__

If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.

  \displaystyle\frac{\sqrt{12}}{\sqrt{3}+3}=\frac{\sqrt{12}}{(\sqrt{3}+3)}\cdot\frac{(\sqrt{3}-3)}{(\sqrt{3}-3)}=\frac{\sqrt{36}-3\sqrt{12}}{3-9}\\\\=\frac{6-3\cdot2\sqrt{3}}{-6}=\boxed{-1+\sqrt{3}}

_____

<em>Additional comment</em>

We "rationalize the denominator" in this way to take advantage of the relation ...

  (a -b)(a +b) = a² -b²

Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.

We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).

3 0
2 years ago
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