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Solnce55 [7]
3 years ago
8

Please help I dont get this☺

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0
The top number would be 288. It's upside down btw
Helen [10]3 years ago
5 0
The top number would be 288 hope it helps:)
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A baker determined the annual profit in dollars from selling cupcakes using p(n)=41n-0.06n2, where n is the number of cupcakes s
Andrej [43]

Answer:

The annual profit is $6384, if the baker sells 240cupcakes

Step-by-step explanation:

Annual profit in dollars from selling cupcakes = p(n)=41n-0.06n^2

where n is the number of cupcakes sold .

We need to find the annual profit if the baker sells 240cupcakes.

If baker sells 240 cupcakes, so we have n = 240

Putting value of n in the given equation and finding profit

p(n)=41n-0.06n^2\\Put\:n=240\\p(240)=41(240)-0.06(240)^2\\p(240)=9840-0.06(57600)\\p(240)=9840-3456\\p(240)=6384

So, The annual profit is $6384, if the baker sells 240cupcakes

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3 years ago
Product A
Savatey [412]

Answer:

I would go with C......

6 0
3 years ago
A store sells jump ropes. Each jump rope costs the same amount. During a sale, the store reduces the price of each jump rope by
Tom [10]

Answer:

The jump rope cost $8.79 before the sale.

Step-by-step explanation:

She spent 15.08 on 2 while they were on sale. I divided 15.08 by 2 to find what each one cost individually on sale, which is $7.54. Then add $1.25 to $7.54= $8.79

4 0
3 years ago
56.4059 - 4.837 Estimate by rounding to the ones​
sergij07 [2.7K]

Answer:

Step-by-step explanation:

56.4059 - 4.837 = 56 - 5 = 51

3 0
3 years ago
The CEO of a clothing company estimates that 52% of customers will make a purchase. Part A: How many customers should a salesper
4vir4ik [10]

Answer:

(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

Step-by-step explanation:

Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.

The probability that a customer makes a purchase is, <em>p</em> = 0.52.

The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

(a)

Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.52}{0.52}\\=0.9231

This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b)

Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

P(X=3)=(1-0.52)^{3}\times0.52\\=0.110592\times 0.52\\=0.05750784\\\approx 0.058

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

8 0
3 years ago
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