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krek1111 [17]
3 years ago
6

quadrilateral DEFG has vertices at D(1,0), E(-2,-2), F(2,4), and G(6,-3). Find the vertices of D’E’F’G’ after a translations of

4 units right and 5 units down
Mathematics
1 answer:
Korvikt [17]3 years ago
8 0
D’(5,-5), E’(2,-7), F’(6,-1), G’(10,-8)
Since it’s four units right you would add 4 to the x value and 5 units down so you subtract 5 from the y value.
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$(x) = -22 +22. - 114
galina1969 [7]

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a

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Inverse of f(x)=-5x+15
Otrada [13]

f(x) = -5x - 15


Let y = f(x)


y = -5x - 15


Switch the x and y places, and solve for y:


x = -5y - 15


-5y = x + 15


y = (x + 15)/-5


y = -(x/5) - 3


So the inverse of : f(x) = -5x - 15 is


-x/5 - 3

5 0
3 years ago
Find the value of k by<br>quardractic equation two real and equal roots<br>5x - 2kx +20=0​
kotegsom [21]

Answer:

k = +10 or -10

Step-by-step explanation:

It's given in the question that the roots of the eqn. are real and equal. So , the discriminant of the eqn. should be equal to 0.

=  >  {b}^{2}  - 4ac = 0

=  >  {( - 2k)}^{2}  - 4 \times 5 \times 20 = 0

=  > 4 {k}^{2}  - 400 = 0

=  > 4( {k}^{2}  - 100) = 0

=  >  {k}^{2}  - 100 = 0

=  > k =  \sqrt{100}  =  + 10 \: or \:  - 10

3 0
2 years ago
Read 2 more answers
From the photo below can someone solve question 50 please.
Pie
Question 50.

a. Description

You walk 0.5 miles during 10 minutes, stop and wait for the bus during 4 minutes, then ride the bus for 2 miles during 4 minutes.

b. slopes

the slope of each line represents the average speed of every track.

1) first track

slope = 0.5 miles / 10 minutes = 0.05 miles / minutes.

Given that the slope is constant, you walked at a constant speed of 0.05 miles/minute.

2) second track

slope = 0 => you didn,t move (you were waiting the bus)

3) third track

slope = (2.5 - 0.5) miles / (18 min - 14 min) = 2 miles / 4 min = 0.5 miles / min

means the speed of the bus was constant and equal to 0.5 miles / min.
6 0
3 years ago
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