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Ahat [919]
3 years ago
10

Please help!!!!!!!!!!!

Mathematics
1 answer:
Temka [501]3 years ago
4 0

9514 1404 393

Answer:

  (d)  h = 2A/b

Step-by-step explanation:

Multiply both sides of the equation by the inverse of the coefficient of h.

  A = \dfrac{1}{2}bh=\dfrac{b}{2}\cdot h\\\\\dfrac{2}{b}\cdot A=h\\\\\boxed{h=\dfrac{2A}{b}}

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18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

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So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

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substituting that value in for x

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Substituting this y value to solve for x gives:

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Answer:

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Step-by-step explanation:

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