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arlik [135]
3 years ago
11

Simplify the expression

Mathematics
2 answers:
yan [13]3 years ago
8 0

cube root of 8 is 2

factors of 24= 2*2*2*3

cube root of 24 = 2∛3

Under cube root we have x and x⁵

so multiplying , x*x⁵ we have x⁶

∛x⁶ = x²

so we have ∛8x * ∛24x⁵ equal to 2*2*x²∛3

so answer is 4x² ∛3

option C is the correct answer

kvv77 [185]3 years ago
6 0

option C is the correct answer

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Lelechka [254]

Answer:

equilateral triangle

Step-by-step explanation:

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2 years ago
What is the degree of the polynomial and what the y-intercept
Arada [10]

Answer:

Polynom degree: 5

Y intercept point: (0, 80)

Step-by-step explanation:

P(x)=(x+5)(x+4)²(x+1)²

When you expand, the highest power of x is 1 for first term (x+5), 2 for second term (x+4)² and again 2 for (x+1)². Overall, x⁵ will be the x term with highest power. So the degree of the polynom is 5.

The y intercept, i.e. intersection with OY axis, happens for x=0. Thus, P(0)=5×4²×1²=5×16=80. The y intercept point is (0, 80)

5 0
2 years ago
Complete the equation of the line through (-8,-2)(-4,6)<br> use exact numbers
Firdavs [7]

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y = 2x + 14

Step-by-step explanation:

Hope this helps!!!

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In other words,

The slope is 2.

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6 0
2 years ago
Determine the translation
arsen [322]

Answer:

<em>1 unit left and 7 units up</em>

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7 0
2 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

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P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
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