Question

How do you Subtract 9x^2 + 22x - 46 from 12x^2 - 8x + 12.

Answer 1

Subtract the $x^2$ terms from each other, then the $x$ terms, then the ones without any $x$ whatsoever.

$(12x^2 - 8x + 12) - (9x^2 +22x-46)$

First, we'll subtract $9x^2$ from $12x^2$

$12x^2-9x^2- = 3x^2$

Result: $3x^2$

Next, we'll subtract $22x$ from $-8x$

$-8x - 22x = -30x$

Result: $-30x$

Finally, we'll subtract $-46$ from $12$

$12-(-46) = 12+46 = 58$

Result: $58$

Now, we can add these 3 results together.

First, we had $3x^2$, then $-30x$, and finally $58$.

Thus, our subtraction of

$(12x^2 - 8x + 12) - (9x^2 +22x-46)$

equals

$3x^2-30x+58$