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Harman [31]
1 year ago
8

Elvera Hilton earns $12 an hour at her job. The hours she worked during each of the last four weeks are shown below

Mathematics
1 answer:
Minchanka [31]1 year ago
6 0

Answer:

12x7 4 times add it up u got the anwser

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3. The length of a living room is 12 feet and its width is 10.5 feet. The length of the room is being
Liono4ka [1.6K]

Since you're adding x feet to the length which is 12 feet:

New area: (12+x)10.5

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3 years ago
The net of a cube is shown. If the length of each edge of the cube is 10 cm, find the surface area of the cube.
Digiron [165]

Answer:The surface area of the cube is 100 cm.

Step-by-step explanation:

So since a cube has six faces and all of its lengths are equal. we could use the equation.

10^2 *6= 100 *6= 600

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2 years ago
What is the percent increase of 16 to 20
mojhsa [17]
Hey You!

16 - 20 / 16 * 100 = 25

The percentage increase from 16 to 20 is 25%. =)
6 0
3 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
2 years ago
Help!!!!! Not the top one by the way..!
OverLord2011 [107]

Answer:

\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}

3 0
3 years ago
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