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3 years ago

A bakery makes 4 dozen raisin muffins and 8 dozen blueberry muffins. A dozen is 12 muffins.

Mathematics

1 answer:

swat323 years ago

7 0

Answer:

144

Step-by-step explanation:

8x12 = 96 and 4x12= 48 and 96+48= 144

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the number 1 is written on a piece of paper and then passed around the room to each of the 50 students in turn. each of the stud

Gnom [1K]

Answer:

The last term on the paper after 50 students = $2^{(50)} -1$

Step-by-step explanation:

The general term of the equation:

Here, the first term = 1

Second term = 2(1) + 1 = 3 = 4 - 1 = $2^{2} - 1$

Third Term = 2(a2) + 1 = 2(3) + 1 = 7 = 8 -1 = $2^{3} - 1$

Fourth term = 2( a3) + 1 = 2(7) + 1 = 15 = 16 - 1 = $2^{3} - 1$

Continuing this way, we get

Last term : $a_n = 2^n -1$

So, the 50th term of this sequence is

$a_{(50)} = 2^{(50)} -1$

Hence, the last term on the paper after 50th student changes it = $2^{(50)} -1$

4 0

3 years ago

Please help me with this problem. I'm kind of stuck and don't know what to do.

Flauer [41]

Try this option:

1) if csc(u)=9, then 1/sin(u)=9 and sin(u)=1/9;

2) if sin(u)=1/9, then cos(u):

$cos(u)=\sqrt{1-sin^2(u)}=\sqrt{1-\frac{1}{81}}=\frac{4\sqrt{5}}{9};$

3) $if \ sin(u)=\frac{1}{9} \ and \ cos(u)=\frac{4\sqrt{5}}{9}, then$

$sin(2u)=2sin(u)*cos(u)=\frac{8\sqrt{5}}{81};$

$cos(2u)=cos^2(u)-sin^2(u)=\frac{80}{81}-\frac{1}{81}=\frac{79}{81};$

$tan(2u)=\frac{sin(2u)}{cos(2u)}=\frac{\frac{8\sqrt{5}}{81}}{\frac{79}{81} }=\frac{8\sqrt{5}}{79}.$

8 0

2 years ago

Let b = 8.

Serhud [2]

the answer is B.12 because 8*2=16 and 28-16=12

hope i helped

3 0

3 years ago

At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl

Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

$n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.$

Let 'p' represents the number of students who take all the three languages, then

$n(A\cap B\cap C)=p.$

Also,

$n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).$

From here, we get after subtracting equation(c) from (b) that

$n(A\cap B)=n(A\cap C)=14.$

Therefore,

$p=14+14-24=4,$ and from equation (a), we find

$n(B\cap C)=24-14=10.$

Thus,

$n(A\cap B\cap C)=4$ and

$n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.$

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0

3 years ago

Find the area of the circle and enter your answer below. Leave Pl in the answer (do not multiply by Pl) Area = πm2 15 m

jolli1 [7]

Answer:

225π

Step-by-step explanation:

Since we are given that m is equivalent to 15 we can plug it into the Area equation given to us like so:

Area = πm²

Area = π15²

Area = π225

4 0

2 years ago