Question

If anyone is willing to help me, I will greatly appreciate it. I can’t afford to fail… I need to graduate so I can achieve my goal!
Question 7
Using this data for the 200 coin tosses:
a. What is the deviation for the 200 tosses?
b. How does increasing the total number of coin tosses from 10 to 100 affect the deviation?
c. How does increasing the number of tosses from 100 to 200 (or more) affect the deviation?
d. What two important probability principles were established in this exercise?

Answer 1

Answer:

1) you're going to have to flip the coins (or fake numbers) for the experimental trials.

2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.

When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.

|(100-50)| ÷ 50 = 50÷50 = 1.00

So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.

Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:

|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!

Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

Answer 2

Answer:

I believe it is C.

I hope you pass! Keep praying and asking the Lord to help you!

Because He will :) (I can promise you that, just have faith, my friend.)

God bless, have a nice day!