Add the KE increase and the work done against friction.
The final velocity is twice the average, or 3.0 m/s
The final KE is (1/2)*25*3^2 = 112.5 J
The friction work done is 6*3.8 = 22.8 J
hope this is correct
Answer: Point A is the answer for the potential energy. Point D is the answer for the kinetic energy.
Explanation:
Answer:
Explanation:
E₀ = 229.1 V/m
E = E₀ / √2 = 229.1 / 1.414 = 162 V/m
B = E / c ( c is velocity of em waves )
= 162 / (3 x 10⁸) = 54 x 10⁻⁸ T
rate of energy flow = ( E x B ) / μ₀
= 162 x 54 x 10⁻⁸ / 4π x 10⁻⁷
= 69.65 W per m².
Answer: C. Meyer did not leave gaps while Mendeleev did.
Explanation: Mendeleev's table was table different from Meyer's table because Meyer did not leave gaps while Mendeleev did.
Answer:
Force plane exert on pilot = 4270 N
Explanation:
first convert radius and speed to ms
using formula from force we know that
mass = weight/ gravity = 700 N/ 9.8N/kg= 71.4 kg
Fc= N-mg
N= Fc+ mg As Fc = mv²/R
N= mv²/R + mg
taking m common
N= m( v²/R +g)
= 71.4( (200)²/ 800 + 9.8 )
Force = 4270 N