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Agata [3.3K]
3 years ago
8

A 0.50 mm-wide slit is illuminated by light of wavelength 500 nm.What is the width of the central maximum on a screen 2.0m behin

d the slit?
Physics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

0.004 m

Explanation:

For light passing through a single slit, the position of the nth-minimum in the diffraction pattern is given by

y=\frac{n\lambda D}{d}

where

\lambda is the wavelength

D is the distance of the screen from the slit

d is the width of the slit

Therefore, the width of the central maximum is equal to twice the value of y for n=1 (first minimum):

w=2\frac{\lambda D}{d}

where we have

\lambda=500 nm = 5\cdot 10^{-7}m is the wavelength

D = 2.0 m is the distance of the screen

d=0.50 mm=5\cdot 10^{-4}m is the width of the slit

Substituting, we find

w=2\frac{(5\cdot 10^{-7} m)(2.0 m)}{5\cdot 10^{-4} m}=0.004 m

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