<h3>☂︎ Answer :- </h3>
<h3>☂︎ Solution :- </h3>
- LCM of 5 , 18 , 25 and 27 = 2 × 3³ × 5²
- 2 and 3 have odd powers . To get a perfect square, we need to make the powers of 2 and 3 even . The powers of 5 is already even .
In other words , the LCM of 5 , 18 , 25 and 27 can be made a perfect square if it is multiplied by 2 × 3 .
The least perfect square greater that the LCM ,
☞︎︎︎ 2 × 3³ × 5² × 2 × 3
☞︎︎︎ 2² × 3⁴ × 5²
☞︎︎︎ 4 × 81 × 85
☞︎︎︎ 100 × 81
☞︎︎︎ 8100
8100 is the least perfect square which is exactly divisible by each of the numbers 5 , 18 , 25 , 27 .
<span><u>1/3x - 1/2y = 1</u>
At the 'x' intercept, y=0 , and the equation is 1/3 x = 1
Multiply each side by 3 : <em>x = 3 </em> <== the x-intercept
At the 'y' intercept, x=0, and the equation is -1/2 y = 1
Multiply each side by 2 : - y = 2
Multiply each side by -1 : <em> y = -2 </em> <== the y-intercept
</span>
The equation is(√7)^6x = 49x - 6
This equation can be solved by iteration.
Rearranging:
x = ( (√7)^6x + 6 )/49
We start with a value of x = 3.
This value can be substituted to the right side and new value of x can be obtained. This new value can be substituted again to the right side of the equation and another new value for x is obtained. This process is repeated until the old and new values of x are the same.
The result is,x = 0.5
Answer:
11 0ver 54
Step-by-step explanation:
