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rodikova [14]
3 years ago
12

Can someone help me ?

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0
Yes. I will help you with anything
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How much larger is 400 than 40?
dlinn [17]
360

400 - 40 = 360

Did I help? Say thanks on my profile!
8 0
3 years ago
Read 2 more answers
Help pls I really need this
Varvara68 [4.7K]

Answer:

{2 , 4} is the answer of this question.

7 0
3 years ago
URGENT!! 25 points. help on C please. this assignment is already late
andrew-mc [135]

Answer:

7+(11-4\times 2)=10

Step-by-step explanation:

So, this question involves you to play around with the numbers and the operations a bit. I've come up with a solution, but perhaps there are others as well.

So, we have:

7\text{ } 11\text{ } 4\text{ } 2\text{ } =\text{ } 10

So, what we can do is, for instance, multiply 4 and 2. Subtract that into 11. And then add the difference to 7. Thus:

7+(11-4\times 2)=10

This is a true number sentence. Let's do it to make sure.

First, do the operations inside the parentheses.

Multiplication comes first, so multiply:

7+(11-8)=10

Again, do the parentheses first. Subtract:

7+(3)=10

Now add:

10=10

So our answer is correct :)

5 0
3 years ago
At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g
Tresset [83]

Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

n(A \cap G) = 35

n(G \cap S) = 29

Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

6 0
3 years ago
What is the slope of this graph?<br> a. 4<br> b. -4<br> c. -1/4 <br> d. 1/4
kykrilka [37]

The answer is -4 i just did the test

6 0
3 years ago
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