How would you solve this polynomial Y=x^3-x^2-x-15

Leni [432]

Answer:

(x + 9)(5x - 1)

Step-by-step explanation:

Given

5x² + 44x - 9

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 5 × - 9 = - 45 and sum = + 44

The factors are + 45 and - 1

Use these factors to split the x- term

5x² + 45x - x - 9 ( factor the first/second and third/fourth terms )

= 5x(x + 9) - 1(x + 9) ← factor out (x + 9) from each term

= (x + 9)(5x - 1) ← in factored form

6 0

3 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

3 years ago

Help me please !!!!!!!!!!!

Mkey [24]

Answer:

s=5

Step-by-step explanation:

As you can see, you have a whole block that is 20. Then you have another block that is broken down to 4 squares.

So....

4s=20

divide 4 to 4s

divide 4 by 20

so s=5

8 0

3 years ago

Read 2 more answers

What is the imaginary part of the following complex number -31?

Alex787 [66]

Answer:

Step-by-step explanation:

-31 + 0i

Imaginary part = 0

4 0

2 years ago

Find the equation of the line that passes through points (3,5) and (-6,2). Write the equation in slope intercept form.

andrezito [222]

1) gradient of line = Δ y ÷ Δ x
= (5 -2) ÷ (3 - (-6))
= ¹/₃

using the point-slope form (y-y₁) = m(x-x₁)
using (3,5)
(y - 5) = ¹/₃ (x -3)
 y - 5 = ¹/₃x - 1
⇒ y = ¹/₃ x + 4 [OPTION D]

2) y = 2x + 5 .... (1)
 y = ¹/₂ x + 6 .... (2)

by substituting y in (1) for y in (2)

2x + 5 = ¹/₂ x + 6
 ³/₂ x = 1
x = ²/₃

by substituting found x (2)

 y = ¹/₂ (²/₃) + 6
y = ¹⁹/₃

∴ common point is (²/₃ , ¹⁹/₃) thus answer is FALSE [OPTION B]

3) Yes [OPTION A]
This is because the both have a gradient of 5 and if they have the same gradient then that means that the two lines are parallel to each other.

4) No [OPTION B]
Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other. Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.

6 0

3 years ago