As we know that cotx= 1/tanx
cot36° = 1/tan36°
=>cot36°= 1/0.726543
=>so cot 36°= 1.376382
So correct answer is option D.
HOPR YOU LIKED.
How would you solve this polynomial Y=x^3-x^2-x-15
1 answer:
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As we know that cotx= 1/tanx
cot36° = 1/tan36°
=>cot36°= 1/0.726543
=>so cot 36°= 1.376382
So correct answer is option D.
HOPR YOU LIKED.
Answer:
1, 5, 2, 4, 3, 7, 6
Step-by-step explanation:
After dividing by the leading coefficient, each equation can be put into the form ...
x² + y² + ax +by +c = 0
Subtracting c and separately completing the square for x-terms and y-terms, we get ...
x² + ax + (a/2)² + y² + by + (b/2)² = -c + (a/2)² + (b/2)²
(x +a/2)² + (y +b/2)² = r² = (a/2)² + (b/2)² -c . . . . . rewrite in standard form
Ordering by the square of the radius length will match the ordering by radius length, so we just need to compute (a/2)² +(b/2)² -c for each given equation. I find it convenient to let a calculator or spreadsheet do this calculation (see attached).
In the order the equations are given, the square of the radius is ...
3, 18, 45, 23, 5, 117, 46
So the order of the equations from smallest radius to largest is ...
1, 5, 2, 4, 3, 7, 6
First move all terms to one side:
Then all terms on the left side share a common factor of :
The zero product product property says that if , then
or
. So either
or
.